A podiatrist asks us to make a preparation of 10 ml of disinfectant alcohol and 5 ml of the Coll odium, but there are always clubbers.

If we dissect the composition of collodion then we notice that the main constituent is ether. So I would split 10 ml of alcohol denat here into 5 ml ether and 5 ml of rubbing alcohol. Instead of ether, acetone may also qualify?